Thread: Ask me about C / C++

Ahh, I never knew that.

And... You say it is "++a", I thought it was "a++"...

Well, whichever it is, I never used that because I was experimenting with different numbers.

I think that ++a; does it before, while a++; would do it after.

If that's right, then this:

Code:

int a = 0;
int b = ++a;

Would make a and b equal to 1, while having it after a would make b equal 0 and a equal 1;

Yes. But behind the scenes, it's a little more complicated than that.

Code:

int a = 0;
int b = a++;
//b equals 0 here, while a = 1

Here's what actually happened.
a was created and initialized to zero
a was copied
a was incremented
b was created, then initialized to the copy

Code:

int a = 0;
int b = ++a;
//a and b both equal 1

a was created and initialized to 0
a was incremented
b was created and initialized to zero

The difference is that copy. Copying takes time and in the case a few posts ago, a copy is not needed and just wastes ram and cpu power. Optimizing software is all about removing extra steps.

Ohhhhhh, I seee.

I had no idea, I guess I need to learn more about optimization then.

Thanks for the information.

Yeah, it's good to learn some of that. When learning a language, always ask why one technique is better than another. Optimizers are specialists, there are very few of us, but we are in high demand. I'm probably in the less than 1% of programmers who can optimize at an assembly level.

Use ++a when you don't explicitly need the pre-saved value. People who put a++ in all their loops are a pet peeve of mine. It doesn't really matter in the integer case, but if you're writing some insane iterator that has to do real work with lots of data, it will make a difference.

Me too, I ever seen post-increments in loops for Firefox and other huge programs.

When creating an array, is it possible to define all of its contents manually in one go? I know that in python, you can do

Code:

mylist = [item1, item2, item3]

Can this be done in C++, or would I have to manually access each index, as in

Code:

int mylist[3];
mylist[0] = item1;
mylist[1] = item2;
mylist[2] = item3;

Thanks!

Yeah, that's possible

Code:

int yourlist = { item1, item2, item3 };

Sweeeeet. No idea why I couldn't find that in the tutorials I was using.

Thanks!

Ninja, do you know of any good assembly language tutorials? Know it's not a C/C++ question, but I figured you're the person to ask. See, I'll be learning it at the university next semester, so I'd like to get a jump on it. Being the most computer literate guy, I know some of my friends will ask me for help, so it'd be good to actually know some.

Yes, "The Art of Assembly" by Randall Hyde. You should be able to find it on Amazon.

Ok, thanks. I'll check it out.

I have a question about a piece of code that's supposed to convert a 32 bit number into its base 10 form. Each digit of the 32 bit number is represented as an array value:

N[0] = 0
N[1] = 1
N[2] = 0

..and so on to N[31]. I use 'if' to check each array value and add the base ten value of that digit onto variable 'temp' (that I use for something else earlier) to end up with the base10 number.

My puzzlement is due to the fact that the program only functions properly when the if statement uses negative logic, as below.

Code:

d=2147483648;
for(k=0; k<32; ++k){
	if(N[k]!=0){
		temp = temp + d;
	}
	d/=2;
}

If however I use if(N[k]=1) then the program treats every array value (binary digit) as if it's 1, and I end up with 4294967295, or 2³²-1. This isn't the first time I've had to use a negative statement in order to get it to work. Bear in mind I'm still "fresh out of the box" new to c++ and don't know very much.

if(N[k]=1) is not doing what you think it is What your code is doing is assigning N[k] to 1, and then checking the result of that assignment (which is 1) hence, it's always true.

You want if(N[k]==1)

a = b; //assignment
a == b; //comparison

Take a look for yourself

Code:

#include <iostream>

int main(int, char **){
   int a = 5;
   int b;
   std::cout << b = a << std::endl;
}

Wow. That makes a good deal of sense now! Thanks ninja.

Oh, and while I'm here, I don't suppose you'd know something about urls? What my lil' program did was convert an IP address (like google.com's 66.102.7.99) into four 8-bit binary numbers and then grouped them as a 32 bit number, and converted them back to base ten, which in this example's case would yield 1113982819. I can take that number and enter it as the url and it'll take me to google.com. When I try that for, say, dreamviews.com (IP 208.43.31.59) I get the number 3492486971. That number however returns a 400 error (bad request). I know zip about networking. Seems fascinating though that the numbers can be played with in ways the browser will still understand.

What are you doing to try an get those web pages? A browser won't let you do that. You using libcurl?

So yea, this is nowhere near finished or anything, I'm just using this so I can get the loop working.
It doesn't exit the loop when "done" is said on the first input, which is what I am trying to get to work.

By the way, the code is for a thing I'm doing which has a shitload of links which need to be wrapped in "page[x]="link";"
Just to make my life easier for it.

So uhhh, what on earth is wrong with it? I cannot figure it out.

Code:

#include <iostream>
#include <sstream>

using namespace std;

int main()
{


    string link0;
    string link1;
    string link2;

    string codepart0;
    string codepart1;
    string codepart2;


    cout << "Enter links" << endl;

while (link0 != "done")
{


    cin >> link0;
    codepart0 = "page[0]=\"" + link0 + "\"" + ";";

    cin >> link1;
    codepart1 = "page[1]=\"" + link1 + "\"" + ";";

    cin >> link2;
    codepart2 = "page[2]=\"" + link2 + "\"" + ";";
}

cout << codepart0 << "\n" << codepart1 << "\n" << codepart2 << endl;



    return 0;
}

It's not exiting the loop because it's checking for the "done" string before it ever retrieves the user input in the body of the loop.

In other words, at the point when it checks for "done" (i.e., just prior to entering the loop), link0 has been defined but nothing has been assigned to it yet because it hasn't reached cin. So it proceeds to run through the entire loop regardless of input received. It doesn't check for "done" again until after the loop restarts, i.e., after the 3rd cin.

A simple solution is to do the first cin before entering the loop. That way it is checking a variable that has received an assignment before running through its normal course, giving it the chance to exit if it receives "done."

Does that make sense?

Ahhhhh, yea, that makes sense. Thanks.

There ain't much I can do about that, because of the way I need to do the thing as a whole.

Imma need to totally change my approach.

Originally Posted by ninja9578

What are you doing to try an get those web pages? A browser won't let you do that. You using libcurl?

I'm not using libcurl. I just ping the web address to get an IP and enter that manually into the program, which then converts a 32 bit number into base 10. 1113982819 will take you to google if you enter that into the url bar in Firefox, I assume it'd do the same thing in any browser.. Er, did I misunderstand the question?

Oh, well it doesn't do that in Safari. Your conversion was correct though.